20-x(5x-4)=5(x-x^2)-2

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Solution for 20-x(5x-4)=5(x-x^2)-2 equation: 



20-x(5x-4)=5(x-x^2)-2

We move all terms to the left:

20-x(5x-4)-(5(x-x^2)-2)=0

We multiply parentheses

-(5(x-x^2)-2)-5x^2+4x+20=0



We calculate terms in parentheses: -(5(x-x^2)-2), so:

5(x-x^2)-2

We multiply parentheses

-5x^2+5x-2

Back to the equation:

-(-5x^2+5x-2)



We add all the numbers together, and all the variables

-5x^2-(-5x^2+5x-2)+4x+20=0

We get rid of parentheses

-5x^2+5x^2-5x+4x+2+20=0

We add all the numbers together, and all the variables

-1x+22=0

We move all terms containing x to the left, all other terms to the right

-x=-22

x=-22/-1

x=+22

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